3.30 \(\int \frac {1}{(c+d x) (a+i a \cot (e+f x))^3} \, dx\)

Optimal. Leaf size=449 \[ -\frac {3 i \text {Ci}\left (2 x f+\frac {2 c f}{d}\right ) \sin \left (2 e-\frac {2 c f}{d}\right )}{8 a^3 d}-\frac {i \text {Ci}\left (6 x f+\frac {6 c f}{d}\right ) \sin \left (6 e-\frac {6 c f}{d}\right )}{8 a^3 d}+\frac {3 i \text {Ci}\left (4 x f+\frac {4 c f}{d}\right ) \sin \left (4 e-\frac {4 c f}{d}\right )}{8 a^3 d}-\frac {3 \text {Ci}\left (2 x f+\frac {2 c f}{d}\right ) \cos \left (2 e-\frac {2 c f}{d}\right )}{8 a^3 d}+\frac {3 \text {Ci}\left (4 x f+\frac {4 c f}{d}\right ) \cos \left (4 e-\frac {4 c f}{d}\right )}{8 a^3 d}-\frac {\text {Ci}\left (6 x f+\frac {6 c f}{d}\right ) \cos \left (6 e-\frac {6 c f}{d}\right )}{8 a^3 d}+\frac {3 \sin \left (2 e-\frac {2 c f}{d}\right ) \text {Si}\left (2 x f+\frac {2 c f}{d}\right )}{8 a^3 d}-\frac {3 \sin \left (4 e-\frac {4 c f}{d}\right ) \text {Si}\left (4 x f+\frac {4 c f}{d}\right )}{8 a^3 d}+\frac {\sin \left (6 e-\frac {6 c f}{d}\right ) \text {Si}\left (6 x f+\frac {6 c f}{d}\right )}{8 a^3 d}-\frac {3 i \cos \left (2 e-\frac {2 c f}{d}\right ) \text {Si}\left (2 x f+\frac {2 c f}{d}\right )}{8 a^3 d}+\frac {3 i \cos \left (4 e-\frac {4 c f}{d}\right ) \text {Si}\left (4 x f+\frac {4 c f}{d}\right )}{8 a^3 d}-\frac {i \cos \left (6 e-\frac {6 c f}{d}\right ) \text {Si}\left (6 x f+\frac {6 c f}{d}\right )}{8 a^3 d}+\frac {\log (c+d x)}{8 a^3 d} \]

[Out]

-1/8*Ci(6*c*f/d+6*f*x)*cos(-6*e+6*c*f/d)/a^3/d+3/8*Ci(4*c*f/d+4*f*x)*cos(-4*e+4*c*f/d)/a^3/d-3/8*Ci(2*c*f/d+2*
f*x)*cos(-2*e+2*c*f/d)/a^3/d+1/8*ln(d*x+c)/a^3/d-3/8*I*cos(-2*e+2*c*f/d)*Si(2*c*f/d+2*f*x)/a^3/d+3/8*I*cos(-4*
e+4*c*f/d)*Si(4*c*f/d+4*f*x)/a^3/d-1/8*I*cos(-6*e+6*c*f/d)*Si(6*c*f/d+6*f*x)/a^3/d+1/8*I*Ci(6*c*f/d+6*f*x)*sin
(-6*e+6*c*f/d)/a^3/d-1/8*Si(6*c*f/d+6*f*x)*sin(-6*e+6*c*f/d)/a^3/d-3/8*I*Ci(4*c*f/d+4*f*x)*sin(-4*e+4*c*f/d)/a
^3/d+3/8*Si(4*c*f/d+4*f*x)*sin(-4*e+4*c*f/d)/a^3/d+3/8*I*Ci(2*c*f/d+2*f*x)*sin(-2*e+2*c*f/d)/a^3/d-3/8*Si(2*c*
f/d+2*f*x)*sin(-2*e+2*c*f/d)/a^3/d

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Rubi [A]  time = 1.73, antiderivative size = 449, normalized size of antiderivative = 1.00, number of steps used = 53, number of rules used = 7, integrand size = 23, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.304, Rules used = {3728, 3303, 3299, 3302, 3312, 4406, 4428} \[ -\frac {3 i \text {CosIntegral}\left (\frac {2 c f}{d}+2 f x\right ) \sin \left (2 e-\frac {2 c f}{d}\right )}{8 a^3 d}-\frac {i \text {CosIntegral}\left (\frac {6 c f}{d}+6 f x\right ) \sin \left (6 e-\frac {6 c f}{d}\right )}{8 a^3 d}+\frac {3 i \text {CosIntegral}\left (\frac {4 c f}{d}+4 f x\right ) \sin \left (4 e-\frac {4 c f}{d}\right )}{8 a^3 d}-\frac {3 \text {CosIntegral}\left (\frac {2 c f}{d}+2 f x\right ) \cos \left (2 e-\frac {2 c f}{d}\right )}{8 a^3 d}+\frac {3 \text {CosIntegral}\left (\frac {4 c f}{d}+4 f x\right ) \cos \left (4 e-\frac {4 c f}{d}\right )}{8 a^3 d}-\frac {\text {CosIntegral}\left (\frac {6 c f}{d}+6 f x\right ) \cos \left (6 e-\frac {6 c f}{d}\right )}{8 a^3 d}+\frac {3 \sin \left (2 e-\frac {2 c f}{d}\right ) \text {Si}\left (2 x f+\frac {2 c f}{d}\right )}{8 a^3 d}-\frac {3 \sin \left (4 e-\frac {4 c f}{d}\right ) \text {Si}\left (4 x f+\frac {4 c f}{d}\right )}{8 a^3 d}+\frac {\sin \left (6 e-\frac {6 c f}{d}\right ) \text {Si}\left (6 x f+\frac {6 c f}{d}\right )}{8 a^3 d}-\frac {3 i \cos \left (2 e-\frac {2 c f}{d}\right ) \text {Si}\left (2 x f+\frac {2 c f}{d}\right )}{8 a^3 d}+\frac {3 i \cos \left (4 e-\frac {4 c f}{d}\right ) \text {Si}\left (4 x f+\frac {4 c f}{d}\right )}{8 a^3 d}-\frac {i \cos \left (6 e-\frac {6 c f}{d}\right ) \text {Si}\left (6 x f+\frac {6 c f}{d}\right )}{8 a^3 d}+\frac {\log (c+d x)}{8 a^3 d} \]

Antiderivative was successfully verified.

[In]

Int[1/((c + d*x)*(a + I*a*Cot[e + f*x])^3),x]

[Out]

(-3*Cos[2*e - (2*c*f)/d]*CosIntegral[(2*c*f)/d + 2*f*x])/(8*a^3*d) + (3*Cos[4*e - (4*c*f)/d]*CosIntegral[(4*c*
f)/d + 4*f*x])/(8*a^3*d) - (Cos[6*e - (6*c*f)/d]*CosIntegral[(6*c*f)/d + 6*f*x])/(8*a^3*d) + Log[c + d*x]/(8*a
^3*d) - ((I/8)*CosIntegral[(6*c*f)/d + 6*f*x]*Sin[6*e - (6*c*f)/d])/(a^3*d) + (((3*I)/8)*CosIntegral[(4*c*f)/d
 + 4*f*x]*Sin[4*e - (4*c*f)/d])/(a^3*d) - (((3*I)/8)*CosIntegral[(2*c*f)/d + 2*f*x]*Sin[2*e - (2*c*f)/d])/(a^3
*d) - (((3*I)/8)*Cos[2*e - (2*c*f)/d]*SinIntegral[(2*c*f)/d + 2*f*x])/(a^3*d) + (3*Sin[2*e - (2*c*f)/d]*SinInt
egral[(2*c*f)/d + 2*f*x])/(8*a^3*d) + (((3*I)/8)*Cos[4*e - (4*c*f)/d]*SinIntegral[(4*c*f)/d + 4*f*x])/(a^3*d)
- (3*Sin[4*e - (4*c*f)/d]*SinIntegral[(4*c*f)/d + 4*f*x])/(8*a^3*d) - ((I/8)*Cos[6*e - (6*c*f)/d]*SinIntegral[
(6*c*f)/d + 6*f*x])/(a^3*d) + (Sin[6*e - (6*c*f)/d]*SinIntegral[(6*c*f)/d + 6*f*x])/(8*a^3*d)

Rule 3299

Int[sin[(e_.) + (f_.)*(x_)]/((c_.) + (d_.)*(x_)), x_Symbol] :> Simp[SinIntegral[e + f*x]/d, x] /; FreeQ[{c, d,
 e, f}, x] && EqQ[d*e - c*f, 0]

Rule 3302

Int[sin[(e_.) + (f_.)*(x_)]/((c_.) + (d_.)*(x_)), x_Symbol] :> Simp[CosIntegral[e - Pi/2 + f*x]/d, x] /; FreeQ
[{c, d, e, f}, x] && EqQ[d*(e - Pi/2) - c*f, 0]

Rule 3303

Int[sin[(e_.) + (f_.)*(x_)]/((c_.) + (d_.)*(x_)), x_Symbol] :> Dist[Cos[(d*e - c*f)/d], Int[Sin[(c*f)/d + f*x]
/(c + d*x), x], x] + Dist[Sin[(d*e - c*f)/d], Int[Cos[(c*f)/d + f*x]/(c + d*x), x], x] /; FreeQ[{c, d, e, f},
x] && NeQ[d*e - c*f, 0]

Rule 3312

Int[((c_.) + (d_.)*(x_))^(m_)*sin[(e_.) + (f_.)*(x_)]^(n_), x_Symbol] :> Int[ExpandTrigReduce[(c + d*x)^m, Sin
[e + f*x]^n, x], x] /; FreeQ[{c, d, e, f, m}, x] && IGtQ[n, 1] && ( !RationalQ[m] || (GeQ[m, -1] && LtQ[m, 1])
)

Rule 3728

Int[((c_.) + (d_.)*(x_))^(m_)*((a_) + (b_.)*tan[(e_.) + (f_.)*(x_)])^(n_), x_Symbol] :> Int[ExpandIntegrand[(c
 + d*x)^m, (1/(2*a) + Cos[2*e + 2*f*x]/(2*a) + Sin[2*e + 2*f*x]/(2*b))^(-n), x], x] /; FreeQ[{a, b, c, d, e, f
}, x] && EqQ[a^2 + b^2, 0] && ILtQ[m, 0] && ILtQ[n, 0]

Rule 4406

Int[Cos[(a_.) + (b_.)*(x_)]^(p_.)*((c_.) + (d_.)*(x_))^(m_.)*Sin[(a_.) + (b_.)*(x_)]^(n_.), x_Symbol] :> Int[E
xpandTrigReduce[(c + d*x)^m, Sin[a + b*x]^n*Cos[a + b*x]^p, x], x] /; FreeQ[{a, b, c, d, m}, x] && IGtQ[n, 0]
&& IGtQ[p, 0]

Rule 4428

Int[((e_.) + (f_.)*(x_))^(m_.)*Sin[(a_.) + (b_.)*(x_)]^(p_.)*Sin[(c_.) + (d_.)*(x_)]^(q_.), x_Symbol] :> Int[E
xpandTrigReduce[(e + f*x)^m, Sin[a + b*x]^p*Sin[c + d*x]^q, x], x] /; FreeQ[{a, b, c, d, e, f}, x] && IGtQ[p,
0] && IGtQ[q, 0] && IntegerQ[m]

Rubi steps

\begin {align*} \int \frac {1}{(c+d x) (a+i a \cot (e+f x))^3} \, dx &=\int \left (\frac {1}{8 a^3 (c+d x)}-\frac {3 \cos (2 e+2 f x)}{8 a^3 (c+d x)}+\frac {3 \cos ^2(2 e+2 f x)}{8 a^3 (c+d x)}-\frac {\cos ^3(2 e+2 f x)}{8 a^3 (c+d x)}-\frac {3 i \sin (2 e+2 f x)}{8 a^3 (c+d x)}-\frac {3 i \cos ^2(2 e+2 f x) \sin (2 e+2 f x)}{8 a^3 (c+d x)}-\frac {3 \sin ^2(2 e+2 f x)}{8 a^3 (c+d x)}+\frac {i \sin ^3(2 e+2 f x)}{8 a^3 (c+d x)}+\frac {3 i \sin (4 e+4 f x)}{8 a^3 (c+d x)}+\frac {3 \sin (2 e+2 f x) \sin (4 e+4 f x)}{16 a^3 (c+d x)}\right ) \, dx\\ &=\frac {\log (c+d x)}{8 a^3 d}+\frac {i \int \frac {\sin ^3(2 e+2 f x)}{c+d x} \, dx}{8 a^3}-\frac {(3 i) \int \frac {\sin (2 e+2 f x)}{c+d x} \, dx}{8 a^3}-\frac {(3 i) \int \frac {\cos ^2(2 e+2 f x) \sin (2 e+2 f x)}{c+d x} \, dx}{8 a^3}+\frac {(3 i) \int \frac {\sin (4 e+4 f x)}{c+d x} \, dx}{8 a^3}-\frac {\int \frac {\cos ^3(2 e+2 f x)}{c+d x} \, dx}{8 a^3}+\frac {3 \int \frac {\sin (2 e+2 f x) \sin (4 e+4 f x)}{c+d x} \, dx}{16 a^3}-\frac {3 \int \frac {\cos (2 e+2 f x)}{c+d x} \, dx}{8 a^3}+\frac {3 \int \frac {\cos ^2(2 e+2 f x)}{c+d x} \, dx}{8 a^3}-\frac {3 \int \frac {\sin ^2(2 e+2 f x)}{c+d x} \, dx}{8 a^3}\\ &=\frac {\log (c+d x)}{8 a^3 d}+\frac {i \int \left (\frac {3 \sin (2 e+2 f x)}{4 (c+d x)}-\frac {\sin (6 e+6 f x)}{4 (c+d x)}\right ) \, dx}{8 a^3}-\frac {(3 i) \int \left (\frac {\sin (2 e+2 f x)}{4 (c+d x)}+\frac {\sin (6 e+6 f x)}{4 (c+d x)}\right ) \, dx}{8 a^3}-\frac {\int \left (\frac {3 \cos (2 e+2 f x)}{4 (c+d x)}+\frac {\cos (6 e+6 f x)}{4 (c+d x)}\right ) \, dx}{8 a^3}+\frac {3 \int \left (\frac {\cos (2 e+2 f x)}{2 (c+d x)}-\frac {\cos (6 e+6 f x)}{2 (c+d x)}\right ) \, dx}{16 a^3}-\frac {3 \int \left (\frac {1}{2 (c+d x)}-\frac {\cos (4 e+4 f x)}{2 (c+d x)}\right ) \, dx}{8 a^3}+\frac {3 \int \left (\frac {1}{2 (c+d x)}+\frac {\cos (4 e+4 f x)}{2 (c+d x)}\right ) \, dx}{8 a^3}+\frac {\left (3 i \cos \left (4 e-\frac {4 c f}{d}\right )\right ) \int \frac {\sin \left (\frac {4 c f}{d}+4 f x\right )}{c+d x} \, dx}{8 a^3}-\frac {\left (3 i \cos \left (2 e-\frac {2 c f}{d}\right )\right ) \int \frac {\sin \left (\frac {2 c f}{d}+2 f x\right )}{c+d x} \, dx}{8 a^3}-\frac {\left (3 \cos \left (2 e-\frac {2 c f}{d}\right )\right ) \int \frac {\cos \left (\frac {2 c f}{d}+2 f x\right )}{c+d x} \, dx}{8 a^3}+\frac {\left (3 i \sin \left (4 e-\frac {4 c f}{d}\right )\right ) \int \frac {\cos \left (\frac {4 c f}{d}+4 f x\right )}{c+d x} \, dx}{8 a^3}-\frac {\left (3 i \sin \left (2 e-\frac {2 c f}{d}\right )\right ) \int \frac {\cos \left (\frac {2 c f}{d}+2 f x\right )}{c+d x} \, dx}{8 a^3}+\frac {\left (3 \sin \left (2 e-\frac {2 c f}{d}\right )\right ) \int \frac {\sin \left (\frac {2 c f}{d}+2 f x\right )}{c+d x} \, dx}{8 a^3}\\ &=-\frac {3 \cos \left (2 e-\frac {2 c f}{d}\right ) \text {Ci}\left (\frac {2 c f}{d}+2 f x\right )}{8 a^3 d}+\frac {\log (c+d x)}{8 a^3 d}+\frac {3 i \text {Ci}\left (\frac {4 c f}{d}+4 f x\right ) \sin \left (4 e-\frac {4 c f}{d}\right )}{8 a^3 d}-\frac {3 i \text {Ci}\left (\frac {2 c f}{d}+2 f x\right ) \sin \left (2 e-\frac {2 c f}{d}\right )}{8 a^3 d}-\frac {3 i \cos \left (2 e-\frac {2 c f}{d}\right ) \text {Si}\left (\frac {2 c f}{d}+2 f x\right )}{8 a^3 d}+\frac {3 \sin \left (2 e-\frac {2 c f}{d}\right ) \text {Si}\left (\frac {2 c f}{d}+2 f x\right )}{8 a^3 d}+\frac {3 i \cos \left (4 e-\frac {4 c f}{d}\right ) \text {Si}\left (\frac {4 c f}{d}+4 f x\right )}{8 a^3 d}-\frac {i \int \frac {\sin (6 e+6 f x)}{c+d x} \, dx}{32 a^3}-\frac {(3 i) \int \frac {\sin (6 e+6 f x)}{c+d x} \, dx}{32 a^3}-\frac {\int \frac {\cos (6 e+6 f x)}{c+d x} \, dx}{32 a^3}-\frac {3 \int \frac {\cos (6 e+6 f x)}{c+d x} \, dx}{32 a^3}+2 \frac {3 \int \frac {\cos (4 e+4 f x)}{c+d x} \, dx}{16 a^3}\\ &=-\frac {3 \cos \left (2 e-\frac {2 c f}{d}\right ) \text {Ci}\left (\frac {2 c f}{d}+2 f x\right )}{8 a^3 d}+\frac {\log (c+d x)}{8 a^3 d}+\frac {3 i \text {Ci}\left (\frac {4 c f}{d}+4 f x\right ) \sin \left (4 e-\frac {4 c f}{d}\right )}{8 a^3 d}-\frac {3 i \text {Ci}\left (\frac {2 c f}{d}+2 f x\right ) \sin \left (2 e-\frac {2 c f}{d}\right )}{8 a^3 d}-\frac {3 i \cos \left (2 e-\frac {2 c f}{d}\right ) \text {Si}\left (\frac {2 c f}{d}+2 f x\right )}{8 a^3 d}+\frac {3 \sin \left (2 e-\frac {2 c f}{d}\right ) \text {Si}\left (\frac {2 c f}{d}+2 f x\right )}{8 a^3 d}+\frac {3 i \cos \left (4 e-\frac {4 c f}{d}\right ) \text {Si}\left (\frac {4 c f}{d}+4 f x\right )}{8 a^3 d}-\frac {\left (i \cos \left (6 e-\frac {6 c f}{d}\right )\right ) \int \frac {\sin \left (\frac {6 c f}{d}+6 f x\right )}{c+d x} \, dx}{32 a^3}-\frac {\left (3 i \cos \left (6 e-\frac {6 c f}{d}\right )\right ) \int \frac {\sin \left (\frac {6 c f}{d}+6 f x\right )}{c+d x} \, dx}{32 a^3}-\frac {\cos \left (6 e-\frac {6 c f}{d}\right ) \int \frac {\cos \left (\frac {6 c f}{d}+6 f x\right )}{c+d x} \, dx}{32 a^3}-\frac {\left (3 \cos \left (6 e-\frac {6 c f}{d}\right )\right ) \int \frac {\cos \left (\frac {6 c f}{d}+6 f x\right )}{c+d x} \, dx}{32 a^3}-\frac {\left (i \sin \left (6 e-\frac {6 c f}{d}\right )\right ) \int \frac {\cos \left (\frac {6 c f}{d}+6 f x\right )}{c+d x} \, dx}{32 a^3}-\frac {\left (3 i \sin \left (6 e-\frac {6 c f}{d}\right )\right ) \int \frac {\cos \left (\frac {6 c f}{d}+6 f x\right )}{c+d x} \, dx}{32 a^3}+\frac {\sin \left (6 e-\frac {6 c f}{d}\right ) \int \frac {\sin \left (\frac {6 c f}{d}+6 f x\right )}{c+d x} \, dx}{32 a^3}+\frac {\left (3 \sin \left (6 e-\frac {6 c f}{d}\right )\right ) \int \frac {\sin \left (\frac {6 c f}{d}+6 f x\right )}{c+d x} \, dx}{32 a^3}+2 \left (\frac {\left (3 \cos \left (4 e-\frac {4 c f}{d}\right )\right ) \int \frac {\cos \left (\frac {4 c f}{d}+4 f x\right )}{c+d x} \, dx}{16 a^3}-\frac {\left (3 \sin \left (4 e-\frac {4 c f}{d}\right )\right ) \int \frac {\sin \left (\frac {4 c f}{d}+4 f x\right )}{c+d x} \, dx}{16 a^3}\right )\\ &=-\frac {3 \cos \left (2 e-\frac {2 c f}{d}\right ) \text {Ci}\left (\frac {2 c f}{d}+2 f x\right )}{8 a^3 d}-\frac {\cos \left (6 e-\frac {6 c f}{d}\right ) \text {Ci}\left (\frac {6 c f}{d}+6 f x\right )}{8 a^3 d}+\frac {\log (c+d x)}{8 a^3 d}-\frac {i \text {Ci}\left (\frac {6 c f}{d}+6 f x\right ) \sin \left (6 e-\frac {6 c f}{d}\right )}{8 a^3 d}+\frac {3 i \text {Ci}\left (\frac {4 c f}{d}+4 f x\right ) \sin \left (4 e-\frac {4 c f}{d}\right )}{8 a^3 d}-\frac {3 i \text {Ci}\left (\frac {2 c f}{d}+2 f x\right ) \sin \left (2 e-\frac {2 c f}{d}\right )}{8 a^3 d}-\frac {3 i \cos \left (2 e-\frac {2 c f}{d}\right ) \text {Si}\left (\frac {2 c f}{d}+2 f x\right )}{8 a^3 d}+\frac {3 \sin \left (2 e-\frac {2 c f}{d}\right ) \text {Si}\left (\frac {2 c f}{d}+2 f x\right )}{8 a^3 d}+\frac {3 i \cos \left (4 e-\frac {4 c f}{d}\right ) \text {Si}\left (\frac {4 c f}{d}+4 f x\right )}{8 a^3 d}+2 \left (\frac {3 \cos \left (4 e-\frac {4 c f}{d}\right ) \text {Ci}\left (\frac {4 c f}{d}+4 f x\right )}{16 a^3 d}-\frac {3 \sin \left (4 e-\frac {4 c f}{d}\right ) \text {Si}\left (\frac {4 c f}{d}+4 f x\right )}{16 a^3 d}\right )-\frac {i \cos \left (6 e-\frac {6 c f}{d}\right ) \text {Si}\left (\frac {6 c f}{d}+6 f x\right )}{8 a^3 d}+\frac {\sin \left (6 e-\frac {6 c f}{d}\right ) \text {Si}\left (\frac {6 c f}{d}+6 f x\right )}{8 a^3 d}\\ \end {align*}

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Mathematica [A]  time = 0.58, size = 197, normalized size = 0.44 \[ \frac {-3 \left (\text {Ci}\left (\frac {2 f (c+d x)}{d}\right )+i \text {Si}\left (\frac {2 f (c+d x)}{d}\right )\right ) \left (\cos \left (2 e-\frac {2 c f}{d}\right )+i \sin \left (2 e-\frac {2 c f}{d}\right )\right )+3 \left (\text {Ci}\left (\frac {4 f (c+d x)}{d}\right )+i \text {Si}\left (\frac {4 f (c+d x)}{d}\right )\right ) \left (\cos \left (4 e-\frac {4 c f}{d}\right )+i \sin \left (4 e-\frac {4 c f}{d}\right )\right )-\left (\text {Ci}\left (\frac {6 f (c+d x)}{d}\right )+i \text {Si}\left (\frac {6 f (c+d x)}{d}\right )\right ) \left (\cos \left (6 e-\frac {6 c f}{d}\right )+i \sin \left (6 e-\frac {6 c f}{d}\right )\right )+\log (c+d x)}{8 a^3 d} \]

Antiderivative was successfully verified.

[In]

Integrate[1/((c + d*x)*(a + I*a*Cot[e + f*x])^3),x]

[Out]

(Log[c + d*x] - 3*(Cos[2*e - (2*c*f)/d] + I*Sin[2*e - (2*c*f)/d])*(CosIntegral[(2*f*(c + d*x))/d] + I*SinInteg
ral[(2*f*(c + d*x))/d]) + 3*(Cos[4*e - (4*c*f)/d] + I*Sin[4*e - (4*c*f)/d])*(CosIntegral[(4*f*(c + d*x))/d] +
I*SinIntegral[(4*f*(c + d*x))/d]) - (Cos[6*e - (6*c*f)/d] + I*Sin[6*e - (6*c*f)/d])*(CosIntegral[(6*f*(c + d*x
))/d] + I*SinIntegral[(6*f*(c + d*x))/d]))/(8*a^3*d)

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fricas [A]  time = 0.83, size = 113, normalized size = 0.25 \[ -\frac {{\rm Ei}\left (\frac {6 i \, d f x + 6 i \, c f}{d}\right ) e^{\left (\frac {6 i \, d e - 6 i \, c f}{d}\right )} - 3 \, {\rm Ei}\left (\frac {4 i \, d f x + 4 i \, c f}{d}\right ) e^{\left (\frac {4 i \, d e - 4 i \, c f}{d}\right )} + 3 \, {\rm Ei}\left (\frac {2 i \, d f x + 2 i \, c f}{d}\right ) e^{\left (\frac {2 i \, d e - 2 i \, c f}{d}\right )} - \log \left (\frac {d x + c}{d}\right )}{8 \, a^{3} d} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(d*x+c)/(a+I*a*cot(f*x+e))^3,x, algorithm="fricas")

[Out]

-1/8*(Ei((6*I*d*f*x + 6*I*c*f)/d)*e^((6*I*d*e - 6*I*c*f)/d) - 3*Ei((4*I*d*f*x + 4*I*c*f)/d)*e^((4*I*d*e - 4*I*
c*f)/d) + 3*Ei((2*I*d*f*x + 2*I*c*f)/d)*e^((2*I*d*e - 2*I*c*f)/d) - log((d*x + c)/d))/(a^3*d)

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giac [B]  time = 1.54, size = 1887, normalized size = 4.20 \[ \text {result too large to display} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(d*x+c)/(a+I*a*cot(f*x+e))^3,x, algorithm="giac")

[Out]

-1/8*(cos(6*c*f/d)*cos(e)^6*cos_integral(6*(d*f*x + c*f)/d) - I*cos(e)^6*cos_integral(6*(d*f*x + c*f)/d)*sin(6
*c*f/d) + 6*I*cos(6*c*f/d)*cos(e)^5*cos_integral(6*(d*f*x + c*f)/d)*sin(e) + 6*cos(e)^5*cos_integral(6*(d*f*x
+ c*f)/d)*sin(6*c*f/d)*sin(e) - 15*cos(6*c*f/d)*cos(e)^4*cos_integral(6*(d*f*x + c*f)/d)*sin(e)^2 + 15*I*cos(e
)^4*cos_integral(6*(d*f*x + c*f)/d)*sin(6*c*f/d)*sin(e)^2 - 20*I*cos(6*c*f/d)*cos(e)^3*cos_integral(6*(d*f*x +
 c*f)/d)*sin(e)^3 - 20*cos(e)^3*cos_integral(6*(d*f*x + c*f)/d)*sin(6*c*f/d)*sin(e)^3 + 15*cos(6*c*f/d)*cos(e)
^2*cos_integral(6*(d*f*x + c*f)/d)*sin(e)^4 - 15*I*cos(e)^2*cos_integral(6*(d*f*x + c*f)/d)*sin(6*c*f/d)*sin(e
)^4 + 6*I*cos(6*c*f/d)*cos(e)*cos_integral(6*(d*f*x + c*f)/d)*sin(e)^5 + 6*cos(e)*cos_integral(6*(d*f*x + c*f)
/d)*sin(6*c*f/d)*sin(e)^5 - cos(6*c*f/d)*cos_integral(6*(d*f*x + c*f)/d)*sin(e)^6 + I*cos_integral(6*(d*f*x +
c*f)/d)*sin(6*c*f/d)*sin(e)^6 + I*cos(6*c*f/d)*cos(e)^6*sin_integral(6*(d*f*x + c*f)/d) + cos(e)^6*sin(6*c*f/d
)*sin_integral(6*(d*f*x + c*f)/d) - 6*cos(6*c*f/d)*cos(e)^5*sin(e)*sin_integral(6*(d*f*x + c*f)/d) + 6*I*cos(e
)^5*sin(6*c*f/d)*sin(e)*sin_integral(6*(d*f*x + c*f)/d) - 15*I*cos(6*c*f/d)*cos(e)^4*sin(e)^2*sin_integral(6*(
d*f*x + c*f)/d) - 15*cos(e)^4*sin(6*c*f/d)*sin(e)^2*sin_integral(6*(d*f*x + c*f)/d) + 20*cos(6*c*f/d)*cos(e)^3
*sin(e)^3*sin_integral(6*(d*f*x + c*f)/d) - 20*I*cos(e)^3*sin(6*c*f/d)*sin(e)^3*sin_integral(6*(d*f*x + c*f)/d
) + 15*I*cos(6*c*f/d)*cos(e)^2*sin(e)^4*sin_integral(6*(d*f*x + c*f)/d) + 15*cos(e)^2*sin(6*c*f/d)*sin(e)^4*si
n_integral(6*(d*f*x + c*f)/d) - 6*cos(6*c*f/d)*cos(e)*sin(e)^5*sin_integral(6*(d*f*x + c*f)/d) + 6*I*cos(e)*si
n(6*c*f/d)*sin(e)^5*sin_integral(6*(d*f*x + c*f)/d) - I*cos(6*c*f/d)*sin(e)^6*sin_integral(6*(d*f*x + c*f)/d)
- sin(6*c*f/d)*sin(e)^6*sin_integral(6*(d*f*x + c*f)/d) - 3*cos(4*c*f/d)*cos(e)^4*cos_integral(4*(d*f*x + c*f)
/d) + 3*I*cos(e)^4*cos_integral(4*(d*f*x + c*f)/d)*sin(4*c*f/d) - 12*I*cos(4*c*f/d)*cos(e)^3*cos_integral(4*(d
*f*x + c*f)/d)*sin(e) - 12*cos(e)^3*cos_integral(4*(d*f*x + c*f)/d)*sin(4*c*f/d)*sin(e) + 18*cos(4*c*f/d)*cos(
e)^2*cos_integral(4*(d*f*x + c*f)/d)*sin(e)^2 - 18*I*cos(e)^2*cos_integral(4*(d*f*x + c*f)/d)*sin(4*c*f/d)*sin
(e)^2 + 12*I*cos(4*c*f/d)*cos(e)*cos_integral(4*(d*f*x + c*f)/d)*sin(e)^3 + 12*cos(e)*cos_integral(4*(d*f*x +
c*f)/d)*sin(4*c*f/d)*sin(e)^3 - 3*cos(4*c*f/d)*cos_integral(4*(d*f*x + c*f)/d)*sin(e)^4 + 3*I*cos_integral(4*(
d*f*x + c*f)/d)*sin(4*c*f/d)*sin(e)^4 - 3*I*cos(4*c*f/d)*cos(e)^4*sin_integral(4*(d*f*x + c*f)/d) - 3*cos(e)^4
*sin(4*c*f/d)*sin_integral(4*(d*f*x + c*f)/d) + 12*cos(4*c*f/d)*cos(e)^3*sin(e)*sin_integral(4*(d*f*x + c*f)/d
) - 12*I*cos(e)^3*sin(4*c*f/d)*sin(e)*sin_integral(4*(d*f*x + c*f)/d) + 18*I*cos(4*c*f/d)*cos(e)^2*sin(e)^2*si
n_integral(4*(d*f*x + c*f)/d) + 18*cos(e)^2*sin(4*c*f/d)*sin(e)^2*sin_integral(4*(d*f*x + c*f)/d) - 12*cos(4*c
*f/d)*cos(e)*sin(e)^3*sin_integral(4*(d*f*x + c*f)/d) + 12*I*cos(e)*sin(4*c*f/d)*sin(e)^3*sin_integral(4*(d*f*
x + c*f)/d) - 3*I*cos(4*c*f/d)*sin(e)^4*sin_integral(4*(d*f*x + c*f)/d) - 3*sin(4*c*f/d)*sin(e)^4*sin_integral
(4*(d*f*x + c*f)/d) + 3*cos(2*c*f/d)*cos(e)^2*cos_integral(2*(d*f*x + c*f)/d) - 3*I*cos(e)^2*cos_integral(2*(d
*f*x + c*f)/d)*sin(2*c*f/d) + 6*I*cos(2*c*f/d)*cos(e)*cos_integral(2*(d*f*x + c*f)/d)*sin(e) + 6*cos(e)*cos_in
tegral(2*(d*f*x + c*f)/d)*sin(2*c*f/d)*sin(e) - 3*cos(2*c*f/d)*cos_integral(2*(d*f*x + c*f)/d)*sin(e)^2 + 3*I*
cos_integral(2*(d*f*x + c*f)/d)*sin(2*c*f/d)*sin(e)^2 + 3*I*cos(2*c*f/d)*cos(e)^2*sin_integral(2*(d*f*x + c*f)
/d) + 3*cos(e)^2*sin(2*c*f/d)*sin_integral(2*(d*f*x + c*f)/d) - 6*cos(2*c*f/d)*cos(e)*sin(e)*sin_integral(2*(d
*f*x + c*f)/d) + 6*I*cos(e)*sin(2*c*f/d)*sin(e)*sin_integral(2*(d*f*x + c*f)/d) - 3*I*cos(2*c*f/d)*sin(e)^2*si
n_integral(2*(d*f*x + c*f)/d) - 3*sin(2*c*f/d)*sin(e)^2*sin_integral(2*(d*f*x + c*f)/d) - log(d*x + c))/(a^3*d
)

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maple [A]  time = 0.64, size = 560, normalized size = 1.25 \[ \frac {3 i \Si \left (4 f x +4 e +\frac {4 c f -4 d e}{d}\right ) \cos \left (\frac {4 c f -4 d e}{d}\right )}{8 a^{3} d}-\frac {3 i \Ci \left (4 f x +4 e +\frac {4 c f -4 d e}{d}\right ) \sin \left (\frac {4 c f -4 d e}{d}\right )}{8 a^{3} d}-\frac {3 i \Si \left (2 f x +2 e +\frac {2 c f -2 d e}{d}\right ) \cos \left (\frac {2 c f -2 d e}{d}\right )}{8 a^{3} d}+\frac {3 i \Ci \left (2 f x +2 e +\frac {2 c f -2 d e}{d}\right ) \sin \left (\frac {2 c f -2 d e}{d}\right )}{8 a^{3} d}-\frac {3 \Si \left (2 f x +2 e +\frac {2 c f -2 d e}{d}\right ) \sin \left (\frac {2 c f -2 d e}{d}\right )}{8 a^{3} d}-\frac {3 \Ci \left (2 f x +2 e +\frac {2 c f -2 d e}{d}\right ) \cos \left (\frac {2 c f -2 d e}{d}\right )}{8 a^{3} d}-\frac {\Si \left (6 f x +6 e +\frac {6 c f -6 d e}{d}\right ) \sin \left (\frac {6 c f -6 d e}{d}\right )}{8 a^{3} d}-\frac {\Ci \left (6 f x +6 e +\frac {6 c f -6 d e}{d}\right ) \cos \left (\frac {6 c f -6 d e}{d}\right )}{8 a^{3} d}+\frac {3 \Si \left (4 f x +4 e +\frac {4 c f -4 d e}{d}\right ) \sin \left (\frac {4 c f -4 d e}{d}\right )}{8 a^{3} d}+\frac {3 \Ci \left (4 f x +4 e +\frac {4 c f -4 d e}{d}\right ) \cos \left (\frac {4 c f -4 d e}{d}\right )}{8 a^{3} d}+\frac {\ln \left (\left (f x +e \right ) d +c f -d e \right )}{8 a^{3} d}-\frac {i \Si \left (6 f x +6 e +\frac {6 c f -6 d e}{d}\right ) \cos \left (\frac {6 c f -6 d e}{d}\right )}{8 a^{3} d}+\frac {i \Ci \left (6 f x +6 e +\frac {6 c f -6 d e}{d}\right ) \sin \left (\frac {6 c f -6 d e}{d}\right )}{8 a^{3} d} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/(d*x+c)/(a+I*a*cot(f*x+e))^3,x)

[Out]

3/8*I/a^3*Si(4*f*x+4*e+4*(c*f-d*e)/d)*cos(4*(c*f-d*e)/d)/d-3/8*I/a^3*Ci(4*f*x+4*e+4*(c*f-d*e)/d)*sin(4*(c*f-d*
e)/d)/d-3/8*I/a^3*Si(2*f*x+2*e+2*(c*f-d*e)/d)*cos(2*(c*f-d*e)/d)/d+3/8*I/a^3*Ci(2*f*x+2*e+2*(c*f-d*e)/d)*sin(2
*(c*f-d*e)/d)/d-3/8/a^3*Si(2*f*x+2*e+2*(c*f-d*e)/d)*sin(2*(c*f-d*e)/d)/d-3/8/a^3*Ci(2*f*x+2*e+2*(c*f-d*e)/d)*c
os(2*(c*f-d*e)/d)/d-1/8/a^3*Si(6*f*x+6*e+6*(c*f-d*e)/d)*sin(6*(c*f-d*e)/d)/d-1/8/a^3*Ci(6*f*x+6*e+6*(c*f-d*e)/
d)*cos(6*(c*f-d*e)/d)/d+3/8/a^3*Si(4*f*x+4*e+4*(c*f-d*e)/d)*sin(4*(c*f-d*e)/d)/d+3/8/a^3*Ci(4*f*x+4*e+4*(c*f-d
*e)/d)*cos(4*(c*f-d*e)/d)/d+1/8/a^3*ln((f*x+e)*d+c*f-d*e)/d-1/8*I/a^3*Si(6*f*x+6*e+6*(c*f-d*e)/d)*cos(6*(c*f-d
*e)/d)/d+1/8*I/a^3*Ci(6*f*x+6*e+6*(c*f-d*e)/d)*sin(6*(c*f-d*e)/d)/d

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maxima [A]  time = 0.90, size = 275, normalized size = 0.61 \[ \frac {f \cos \left (-\frac {6 \, {\left (d e - c f\right )}}{d}\right ) E_{1}\left (-\frac {6 i \, {\left (f x + e\right )} d - 6 i \, d e + 6 i \, c f}{d}\right ) - 3 \, f \cos \left (-\frac {4 \, {\left (d e - c f\right )}}{d}\right ) E_{1}\left (-\frac {4 i \, {\left (f x + e\right )} d - 4 i \, d e + 4 i \, c f}{d}\right ) + 3 \, f \cos \left (-\frac {2 \, {\left (d e - c f\right )}}{d}\right ) E_{1}\left (-\frac {2 i \, {\left (f x + e\right )} d - 2 i \, d e + 2 i \, c f}{d}\right ) - 3 i \, f E_{1}\left (-\frac {2 i \, {\left (f x + e\right )} d - 2 i \, d e + 2 i \, c f}{d}\right ) \sin \left (-\frac {2 \, {\left (d e - c f\right )}}{d}\right ) + 3 i \, f E_{1}\left (-\frac {4 i \, {\left (f x + e\right )} d - 4 i \, d e + 4 i \, c f}{d}\right ) \sin \left (-\frac {4 \, {\left (d e - c f\right )}}{d}\right ) - i \, f E_{1}\left (-\frac {6 i \, {\left (f x + e\right )} d - 6 i \, d e + 6 i \, c f}{d}\right ) \sin \left (-\frac {6 \, {\left (d e - c f\right )}}{d}\right ) + f \log \left ({\left (f x + e\right )} d - d e + c f\right )}{8 \, a^{3} d f} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(d*x+c)/(a+I*a*cot(f*x+e))^3,x, algorithm="maxima")

[Out]

1/8*(f*cos(-6*(d*e - c*f)/d)*exp_integral_e(1, -(6*I*(f*x + e)*d - 6*I*d*e + 6*I*c*f)/d) - 3*f*cos(-4*(d*e - c
*f)/d)*exp_integral_e(1, -(4*I*(f*x + e)*d - 4*I*d*e + 4*I*c*f)/d) + 3*f*cos(-2*(d*e - c*f)/d)*exp_integral_e(
1, -(2*I*(f*x + e)*d - 2*I*d*e + 2*I*c*f)/d) - 3*I*f*exp_integral_e(1, -(2*I*(f*x + e)*d - 2*I*d*e + 2*I*c*f)/
d)*sin(-2*(d*e - c*f)/d) + 3*I*f*exp_integral_e(1, -(4*I*(f*x + e)*d - 4*I*d*e + 4*I*c*f)/d)*sin(-4*(d*e - c*f
)/d) - I*f*exp_integral_e(1, -(6*I*(f*x + e)*d - 6*I*d*e + 6*I*c*f)/d)*sin(-6*(d*e - c*f)/d) + f*log((f*x + e)
*d - d*e + c*f))/(a^3*d*f)

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mupad [F]  time = 0.00, size = -1, normalized size = -0.00 \[ \int \frac {1}{{\left (a+a\,\mathrm {cot}\left (e+f\,x\right )\,1{}\mathrm {i}\right )}^3\,\left (c+d\,x\right )} \,d x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/((a + a*cot(e + f*x)*1i)^3*(c + d*x)),x)

[Out]

int(1/((a + a*cot(e + f*x)*1i)^3*(c + d*x)), x)

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sympy [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \frac {i \int \frac {1}{c \cot ^{3}{\left (e + f x \right )} - 3 i c \cot ^{2}{\left (e + f x \right )} - 3 c \cot {\left (e + f x \right )} + i c + d x \cot ^{3}{\left (e + f x \right )} - 3 i d x \cot ^{2}{\left (e + f x \right )} - 3 d x \cot {\left (e + f x \right )} + i d x}\, dx}{a^{3}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(d*x+c)/(a+I*a*cot(f*x+e))**3,x)

[Out]

I*Integral(1/(c*cot(e + f*x)**3 - 3*I*c*cot(e + f*x)**2 - 3*c*cot(e + f*x) + I*c + d*x*cot(e + f*x)**3 - 3*I*d
*x*cot(e + f*x)**2 - 3*d*x*cot(e + f*x) + I*d*x), x)/a**3

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